Consetive 3 odd or even values

Ques: Given an array of ints, return true if the array contains either 3 even or 3 odd values all next to each other.

Ans:
package oddorevenin.array;
public class OddorEveninArray {
  public static void main(String[] args) {

        int[] nums = {2, 2, 2, 5, 9};
        System.out.println("Nunber=" + modThree(nums));
    }

    public static boolean modThree(int[] nums) {
        int ecount = 0;
        int ocount = 0;
        int oloop = 0;
        int eloop = 0;
        for (int i = 0; i < nums.length; i++) {
            oloop = i;
            if (nums[oloop] % 2 == 1) {

                for (int j = 0; j < 3; j++) {
                         if (j + i > nums.length - 1) {
                        break;
                    }
                    if (nums[j + i] % 2 == 1) {
                             ocount++;
                        oloop++;
                    }
                    if (ocount == 3) {
                        break;
                    }
                }
                if (ocount < 3) {
                    ocount = 0;
                }
            }
            if (ocount == 3) {
                break;
            }
        }

        /////////////////////////Starting the Even loop
        for (int i = 0; i < nums.length; i++) {
            eloop = i;
            if (nums[eloop] % 2 == 0) {

                for (int j = 0; j < 3; j++) {
                    if (j + i > nums.length - 1) {
                        break;
                    }
                    if (nums[j + i] % 2 == 0) {
                        ecount++;
                        eloop++;
                    }
                    if (ecount == 3) {
                        break;
                    }
                }
                if (ecount < 3) {
                    ecount = 0;
                }
            }
            if (ecount == 3) {
                break;
            }
        }

        return (ocount == 3 || ecount == 3) ? true : false;
    }

}